Latest Success Metrics For Actual 1z0-071 Exam 2022 Realistic Dumps [Q93-Q109]

1z0-071 Oracle

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Latest Success Metrics For Actual 1z0-071 Exam 2022 Realistic Dumps

Updated 1z0-071 Dumps Questions For Oracle Exam

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Let us discuss the objectives of the exam. We’ve already seen that there’s a need to take up the Oracle 1Z0-071 Certification Exam because it’s a prerequisite for the other exams in the business and technical areas of Database Administration. However, there are alternative reasons that should incentivize you to take this examination.

The Oracle 1Z0-071 DBA certification exam is developed by global market leaders like Oracle and is one of their most valued certifications. Bypassing this exam, you’ll be put on the first rung of the database administrator ladder, which will help you move up in your career. The certification provides a benchmark for competency in database administration. It gives employers the ability to measure their staff against the industry’s criteria. Those who pass the CAMS exam with the help of Oracle 1Z0-071 Dumps gain several benefits. Bypassing the ORACLE 1Z0-071 certification exam, you will be able to not just get a promotion but also show your manager that there are no limits on what skills and expertise you have.

If you are looking to take this certification exam, you will need to prepare heavily. It is not the kind of test which you can pass simply by showing up on the day of the exam. You need to know what the ORACLE 1Z0-071 certification is all about, whether this is your first time taking this particular exam or not.

NEW QUESTION 93
View the Exhibit and examine the structure in the EMPLOYEES tables.

Evaluate the following SQL statement:
SELECT employee_id, department_id
FROM employees
WHERE department_id= 50 ORDER BY department_id
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id= 90
UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id= 10;
What would be the outcome of the above SQL statement?

The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.

The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.

The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.

The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.

NEW QUESTION 94
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transactions complete thereby committing the updates? (Choose three.)

when a DBA issues a successful SHUTDOWN TRANSACTIONALstatement and the user then issues a COMMIT

when a CREATE INDEXstatement is executed successfully in the same session

when a COMMITstatement is issued by the same user from another session in the same database instance

when the session logs out successfully

when a DBA issues a successful SHUTDOWN IMMEDIATEstatement and the user then issues a COMMIT

when a CREATE TABLE AS SELECTstatement is executed unsuccessfully in the same session

Explanation/Reference:

NEW QUESTION 95
Examine the structure of the EMPLOYEES table.

You must display the maximum and minimum salaries of employees hired 1 year ago.
Which two statements would provide the correct output? (Choose two.)

SELECT MIN(Salary) minsal, MAX(salary) maxsal
FROM employees
WHERE hire_date < SYSDATE-365
GROUP BY MIN(salary), MAX(salary);

SELECT minsal, maxsal
FROM (SELECT MIN(salary) minsal, MAX(salary) maxsal
FROM employees
WHERE hire_date < SYSDATE-365)
GROUP BY maxsal, minsal;

SELECT minsal, maxsal
FROM (SELECT MIN(salary) minsal, MAX(salary) maxsal
FROM employees
WHERE hire_date < SYSDATE-365
GROUP BY MIN(salary), MAX(salary));

SELECT MIN(Salary), MAX(salary)
FROM (SELECT salary FROM
employees
WHERE hire_date < SYSDATE-365);

NEW QUESTION 96
View the Exhibit and examine the structure in the DEPARTMENTS tables. (Choose two.)

Examine this SQL statement:
SELECT department_id “DEPT_ID”, department_name, ‘b’ FROM
departments
WHERE departments_id=90
UNION
SELECT department_id, department_name DEPT_NAME, ‘a’ FROM
departments
WHERE department_id=10
Which two ORDER BY clauses can be used to sort output?

ORDER BY DEPT_NAME;

ORDER BY DEPT_ID;

ORDER BY ‘b’;

ORDER BY 3;

NEW QUESTION 97
Evaluate the following SELECT statement and view the Exhibit to examine its output:

SELECT constraint_name, constraint_type, search_condition, r_constraint_name, delete_rule, status FROM user_constraints WHERE table_name = ORDERS
Which two statements are true about the output? (Choose two.)

In the second column, indicates a check constraint.

The STATUS column indicates whether the table is currently in use.

The R_CONSTRAINT_NAME column gives the alternative name for the constraint.

The column DELETE_RULE decides the state of the related rows in the child table when the corresponding row is deleted from the parent table.

NEW QUESTION 98
Examine the command:

What does ON DELETE CASCADE imply?

When the BOOKS table is dropped, the BOOK_TRANSACTIONS table is dropped.

When the BOOKS table is dropped, all the rows in the BOOK_TRANSACTIONS table are deleted but the table structure is retained.

When a row in the BOOKS table is deleted, the rows in the BOOK_TRANSACTIONS table whose BOOK_ID matches that of the deleted row in the BOOKS table are also deleted.

When a value in the BOOKS.BOOK_ID column is deleted, the corresponding value is updated in the BOOKS_TRANSACTIONS.BOOK_ID column.

NEW QUESTION 99
Examine the structure of the BOOKS_TRANSACTIONStable:
Name Null? Type
– ————— —————– —————————
TRANSACTION_ID NOT NULL VARCHAR2 (6)
BORROWED_DATE VARCHAR2 (50)
DUE_DATE DATE
BOOK_ID DATE
MEMBER_ID VARCHAR2 (6)
You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM BOOKS_TRANSACTIONS;

SELECT member_id ‘MEMBER ID’, due_date ‘DUE DATE’, ‘$2 AS LATE FEE’ FROM BOOKS_TRANSACTIONS;

SELECT member_id AS “MEMBER ID”, due_date AS “DUE DATE”, ‘$2’ AS “LATE FEE” FROM BOOKS_TRANSACTIONS;

SELECT member_id AS “MEMBER ID”, due_date AS “DUE DATE”, $2 AS “LATE FEE” FROM BOOKS_TRANSACTIONS;

NEW QUESTION 100
View the Exhibit and examine the structure of the PRODUCTS table.

You must display the category with the maximum number of items.
You issue this query:

What is the result?

It generates an error because = is not valid and should be replaced by the IN operator.

It executes successfully but does not give the correct output.

It executes successfully and gives the correct output.

It generate an error because the subquery does not have a GROUP BY clause.

NEW QUESTION 101
Examine the structure of the members table:

Which query can be used to display the last names and city names only for members from the states MO and MI?
A)

B)

C)

D)

Option A

Option B

Option C

Option D

NEW QUESTION 102
Which three statements are true about views in an Oracle Database?

Views can join tables only if they belong to the same schema.

A view can be created that refers to a non-existent table in its defining query.

Views have no object number.

Views have no segment.

Rows inserted into a table using a view are retained in the table if the view is dropped.

A SELECT statement cannot contain a WHERE clause when querying a view containing a WHEREclause in its defining query.

Explanation
Explanation/Reference: https://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_8004.htm#SQLRF01504
https://community.oracle.com/thread/2178948

NEW QUESTION 103
View the exhibits and examine the structures of the COSTS and PROMOTIONS tables.

Evaluate the following SQL statement:
SQL> SELECT prod_id FROM costs
WHERE promo_id IN (SELECT promo_id FROM promotions
WHERE promo_cost < ALL
(SELECT MAX(promo_cost) FROM promotions
GROUP BY (promo_end_date-
promo_begin_date)));
What would be the outcome of the above SQL statement?

It displays prod IDs in the promo with the lowest cost.

It displays prod IDs in the promos with the lowest cost in the same time interval.

It displays prod IDs in the promos with the highest cost in the same time interval.

It displays prod IDs in the promos which cost less than the highest cost in the same time interval.

NEW QUESTION 104
View the Exhibit and examine the structure of ORDERS and ORDER_ITEMS tables.
ORDER_ID is the primary key in the ORDERS table. It is also the foreign key in the ORDER_ITEMS table wherein it is created with the ON DELETE CASCADE option.
Which DELETE statement would execute successfully?

DELETE orders o, order_items IWHERE o.order_id = i.order_id;

DELETEFROM ordersWHERE (SELECT order_idFROM order_items);

DELETE ordersWHERE order_total < 1000;

DELETE order_idFROM ordersWHERE order_total < 1000;

NEW QUESTION 105
Examine the structure of the MARKStable:

Which two statements would execute successfully? (Choose two.)
SELECT SUM(DISTINCT NVL(subject1,0)), MAX(subject1)

FROM marks
WHERE subject1 > subject2;
SELECT student_name subject1

FROM marks
WHERE subject1 > AVG(subject1);
SELECT SUM(subject1+subject2+subject3)

FROM marks
WHERE student_name IS NULL;
SELECT student_name,SUM(subject1)

FROM marks
WHERE student_name LIKE ‘R%’;

NEW QUESTION 106
Which three statements are true about indexes and their administration in an Oracle database?

An INVISIBLE index is not maintained when Data Manipulation Language (DML) is performed on its underlying table.

An index can be created as part of a CREATE TABLE statement.

A DROP INDEX statement always prevents updates to the table during the drop operation

A UNIQUE and non-unique index can be created on the same table column

A descending index is a type of function-based index

If a query filters on an indexed column then it will always be used during execution of the query

NEW QUESTION 107
View the Exhibit and examine the structure of the CUSTOMERS and CUST_HISTORY tables.

The CUSTOMERS table contains the current location of all currently active customers.
The CUST_HISTORY table stores historical details relating to any changes in the location of all current as well as previous customers who are no longer active with the company.
You need to find those customers who have never changed their address.
Which SET operator would you use to get the required output?

INTERSECT

UNION ALL

MINUS

UNION

NEW QUESTION 108
Examine the description of the EMP_DETAILS table given below:

Which two statements are true regarding SQL statements that can be executed on the EMP_DETAIL TABLE?

An EMP_IMAGE column cannot be included in the ORDER BY clause.

You can alter the table to include the NOT NULL constraint on the EMP_IMAGE column.

You cannot add a new column to the table with LONG as the data type.

An EMP_IMAGE column can be included in the GROUP BY clause.

NEW QUESTION 109
Which four statements are true regarding primary and foreign key constraints and the effect they can have on table data?

Only the primary key can be defined at the column and table level.

The foreign key columns and parent table primary key columns must have the same names.

It is possible for child rows that have a foreign key to remain in the child table at the time the parent row is deleted.

A table can have only one primary key but multiple foreign keys.

Primary key and foreign key constraints can be defined at both the column and table level.

A table can have only one primary key and one foreign key.

It is possible for child rows that have a foreign key to be deleted automatically from the child table at the time the parent row is deleted

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